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Home/ Questions/Q 6901881
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:43:45+00:00 2026-05-27T07:43:45+00:00

Anyone could explain what happens memory wise (Stack & Heap) in this example? If

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Anyone could explain what happens memory wise (Stack & Heap) in this example? If I understand it correctly, java stores objects on the heap, so i1 will be on the heap… same with string? But what about i2, considering it is a class field declaration.

public ExampleClass {
   Integer i1=new Integer(1);
   int i2 = 2;
   String str = "abc";
}
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  1. Editorial Team
    Editorial Team
    2026-05-27T07:43:45+00:00Added an answer on May 27, 2026 at 7:43 am

    Nothing happens until you have some code like new ExampleClass(). Once you do that, a new object is allocated on the heap. Included in that will be references to i1, i2, and str. I’m guessing that since you’re not in a method, that i2 will be automatically converted behind the scenes to the equivalent of Integer i2 = new Integer(0). All 3 of these references will be pointing to objects also allocated on the heap. Note that strings are immutable so if there is already a String with the value "abc", then the reference may point to that.

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