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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:23:32+00:00 2026-05-30T08:23:32+00:00

Anyone know how I could go about writing a unix shell script (ksh) that

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Anyone know how I could go about writing a unix shell script (ksh) that would print the first line of any files that match the name “README” in the current and sub directories?

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:23:34+00:00Added an answer on May 30, 2026 at 8:23 am

    Using find with head

    find . -name 'README' -exec head -1 {} \;
    

    Why \;?

    From find manual

    -exec command ;
    Execute command; true if 0 status is returned. All following arguments to find are taken to be arguments to the command until an argument
    consisting of ;' is encountered. The string{}’ is replaced by the current file name being processed everywhere it occurs in the argu‐
    ments to the command, not just in arguments where it is alone, as in some versions of find. Both of these constructions might need to be
    escaped (with a `\’) or quoted to protect them from expansion by the shell
    . See the EXAMPLES section for examples of the use of the -exec
    option. The specified command is run once for each matched file. The command is executed in the starting directory. There are unavoid‐
    able security problems surrounding use of the -exec action; you should use the -execdir option instead.

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