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Home/ Questions/Q 259767
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:17:30+00:00 2026-05-11T22:17:30+00:00

Apologies for asking what’s probably a very obvious question, I’ve been banging my head

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Apologies for asking what’s probably a very obvious question, I’ve been banging my head against this all day + I’m very new to JQuery and JavaScript in general.

I’m running the following:-

<script type="text/javascript">
$(function() {
$.getJSON(
  "http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20(%22UTG.L%22)%0A%09%09&format=json&env=http%3A%2F%2Fdatatables.org%2Falltables.env&callback=?", 
  function(data) {

$.each(data.query.results.row, function(index, item){
    $('#quotes')
    .append(
      $('<p/>')
        .append($('<span class="left"/>').text(item.symbol))
        .append($('<span class="right"/>').text('$'+item.price))
      );
    });

  }
);

});
</script>

I get object undefined var name, i = 0, length = object.length; from firebug – can anyone help me out?

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:17:30+00:00Added an answer on May 11, 2026 at 10:17 pm

    The JSON structure doesn’t know a query.results.row, but a query.results.quote instead. This works:

    console.log(data);
    var quotes = data.query.results.quote;
    for (var q in quotes) {
      $('#quotes')
        .append(
          $('<p/>')
          .append($('<span class="left"/>').text(q))
          .append($('<span class="right"/>').text('$' + quotes[q]))
        );
    }
    });
    

    You are not calling a JSON resource, but a JSONP resource. The callback argument of the url should be a function name and you should use $.getScript.

    myCallback = function(jsonData) {
      ...
    }
    $.getScript("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20(%22UTG.L%22)%0A%09%09&format=json&env=http%3A%2F%2Fdatatables.org%2Falltables.env&callback=myCallback");
    
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