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Home/ Questions/Q 7913707
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T13:54:27+00:00 2026-06-03T13:54:27+00:00

Apologies for the unweildy title, this is a very difficult question to put into

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Apologies for the unweildy title, this is a very difficult question to put into words. This code will explain it much better.

alert(formob.Nam.value); //i work correctly
alert(formob.Num.value); //and me  

name=formob.Nam; 
console.log(name); //[object HTMLInputElement]
console.log("name set "+name.value); //i return 'name set undefined'

num=formob.Num;
console.log(num); //<input type="text" name="Num">
console.log("num set "+num.value); //i return 'num set [value entered]' correctly

Simplified HTML:

<form method="post" class="well" name="FooterCall">
<input type="text" name="Nam">
<input type="text" name="Num">
<button... onmousedown="subajax(this.form...)"..>

Summary:
Two essentially identical fields are being set in a form, but one sets incorrectly when the field is set to a Javascript object.

Thankyou very much in advance for any help that can be offered! 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T13:54:29+00:00Added an answer on June 3, 2026 at 1:54 pm

    if you use the following HTML

    <form method="post" name="formob">
    <input type="text" name="Nam">
    <input type="text" name="Num">
    </form>
    ​
    

    and check this JavaScript where you do not use nameas variable name it should work imho. formob needs to be a reference to the form of course:

    console.log(formob.Nam.value); //i work correctly
    console.log(formob.Num.value); //and me  
    
    xname = formob.Nam;
    console.log(xname); //[object HTMLInputElement]
    console.log("name set " + xname.value); //i return 'name set undefined'
    
    num = formob.Num;
    console.log(num); //<input type="text" name="Num">
    console.log("num set " + num.value); //i return 'num set [value entered]' correctly​
    

    this should work

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