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Home/ Questions/Q 7623541
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T04:43:56+00:00 2026-05-31T04:43:56+00:00

Apologies in advance if this question is badly worded! I have a MySQL table

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Apologies in advance if this question is badly worded!

I have a MySQL table which has a datetime field. How would one count the number of occurrences of each day name, for distinct weeks?

Here is the query I’m trying, and the result it gives from just over 2 weeks of data. It is (obviously) counting every occurrence for each record, whereas I want the output to be either 2 or 3.

SELECT dayname(datetime), COUNT(dayofweek(datetime)) 
   FROM mytable GROUP BY dayofweek(datetime);

+-------------------+----------------------------+
| dayname(datetime) | count(dayofweek(datetime)) |
+-------------------+----------------------------+
| Monday            |                        404 |
| Tuesday           |                        275 |
| Wednesday         |                        251 |
| Thursday          |                        196 |
| Friday            |                        201 |
| Saturday          |                        128 |
+-------------------+----------------------------+

Grouping by week did not solve the problem. I feel as though I need to “count where week is distinct” but I’m not sure if this is possible.

Any guidance is much appreciated, thank you!

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  1. Editorial Team
    Editorial Team
    2026-05-31T04:43:58+00:00Added an answer on May 31, 2026 at 4:43 am

    Try to count distinct values (date part only) of your datetime field. More about COUNT(DISTINCT expr,[expr...]) and DATE(expr) that returns the date part only from datetime field.

    SELECT dayname(datetime), COUNT(distinct date(datetime)) 
    FROM mytable GROUP BY dayname(datetime);
    
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