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Home/ Questions/Q 6092755
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:28:52+00:00 2026-05-23T12:28:52+00:00

Apparently $pid is out of scope here. Shouldn’t it be closed in with the

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Apparently $pid is out of scope here. Shouldn’t it be “closed” in with the function? I’m fairly sure that is how closures work in javascript for example.

According to some articles php closures are broken, so I cannot access this?

So how can $pid be accessed from this closure function?

class MyClass {
  static function getHdvdsCol($pid) {
    $col = new PointColumn();
    $col->key = $pid;
    $col->parser = function($row) {
        print $pid; // Undefined variable: pid
    };
    return $col;
  }
}

$func = MyClass::getHdvdsCol(45);
call_user_func($func, $row);

Edit I have gotten around it with use: $col->parser = function($row) use($pid). However I feel this is ugly.

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:28:53+00:00Added an answer on May 23, 2026 at 12:28 pm

    You need to specify which variables should be closed in this way:

    function($row) use ($pid) { ... }
    
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