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Home/ Questions/Q 705993
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:06:59+00:00 2026-05-14T04:06:59+00:00

Apple advises using the following code to detect whether running on an iPad or

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Apple advises using the following code to detect whether running on an iPad or iPhone/iPod Touch:

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
  // The device is an iPad running iPhone 3.2 or later.
  // [for example, load appropriate iPad nib file]
}
else {
  // The device is an iPhone or iPod touch.
  // [for example, load appropriate iPhone nib file]
}

The problem is that UI_USER_INTERFACE_IDIOM() and UIUserInterfaceIdiomPad are NOT defined in the SDKs prior to 3.2. This seems to completely defeat the purpose of such a function. They can only be compiled and run on iPhone OS 3.2 (iPhone OS 3.2 can only be run on iPad). So if you can use UI_USER_INTERFACE_IDIOM(), the result will always be to indicate an iPad.

If you include this code and target OS 3.1.3 (the most recent iPhone/iPod Touch OS) in order to test your iPhone-bound universal app code, you will get compiler errors since the symbols are not defined in 3.1.3 or earlier, when compiling for iPhone simulator 3.1.3.

If this is the recommended-by-Apple approach to runtime device-detection, what am I doing wrong? Has anyone succeeded using this approach to device-detection?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:07:00+00:00Added an answer on May 14, 2026 at 4:07 am

    I do this to get the code to compile in both 3.1.3 and 3.2:

    BOOL iPad = NO;
    #ifdef UI_USER_INTERFACE_IDIOM
    iPad = (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad);
    #endif
    if (iPad) {
    // iPad specific code here
    } else {
    // iPhone/iPod specific code here
    }
    

    I also wrote a quick blog post about it here:
    http://www.programbles.com/2010/04/03/compiling-conditional-code-in-universal-iphone-ipad-applications/

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