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Home/ Questions/Q 7014957
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:35:23+00:00 2026-05-27T22:35:23+00:00

// Application … Intent i = new Intent(); i.putExtra(EXTRA_FILE_UPLOAD_URIS, mGalleryAdapter.getItems()); Uri[] getItems() { return

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// Application ...
Intent i = new Intent();
i.putExtra(EXTRA_FILE_UPLOAD_URIS, mGalleryAdapter.getItems()); 

Uri[] getItems() { return mItems; }

// Service ...
intent.getParcelableArrayExtra(EXTRA_FILE_UPLOAD_URIS); //works, returns Parcelable[]
Uri[] uris = (Uri[])intent.getParcelableArrayExtra(EXTRA_FILE_UPLOAD_URIS);
// ... Breaks with ClassCastException

Why does the cast to Uri[] break, when Uri is Parcelable?

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:35:24+00:00Added an answer on May 27, 2026 at 10:35 pm

    Unfortunately there is no way to cast like that for arrays in Java. You will have to iterate your array and cast each object individually.

    The reason for this is type Safety, the JVM simply cannot ensure that the contents of your array can be casted to Uri, without having to iterate thru them, which is why you have to iterate them and cast them individually.

    Basically because Parcelable could be inherited by other Objects, there is no guarantee that the Array contains only Uri objects. However casting to a supertype would work since then type safety would be ok.

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