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Home/ Questions/Q 252403
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:40:31+00:00 2026-05-11T21:40:31+00:00

Application.Run(form); Actually I tried to call this from my project. I got this exception.

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Application.Run(form);

Actually I tried to call this from my project. I got this exception. How to solve it? I have already called another Application.Run(frmBind); in my project.

Starting a second message loop on a single thread is not a valid
operation. Use Form.ShowDialog instead.

 static void Main(string[] args)
 {
    frmBind = new frmMain();

    Application.Run(frmBind);

    //args1 = string.Copy(args);
}

This is where I call the Application at first

Now again did it here:

try
{
   // Application.Run( form);
   form.ShowDialog();
}

Here the exception is thrown.

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:40:31+00:00Added an answer on May 11, 2026 at 9:40 pm

    It’s telling you how to solve it:

     form.Show();  
    

    or if you want the new form to be modal:

     form.ShowDialog();
    
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