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Home/ Questions/Q 7520705
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T02:06:55+00:00 2026-05-30T02:06:55+00:00

Applying the standard XSLT copy template, <xsl:template match=@*|node()> <xsl:copy> <xsl:apply-templates select=@*|node()/> </xsl:copy> </xsl:template> to

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Applying the standard XSLT copy template,

<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

to the JBoss AS 7 standalone.xml, leads to loss of parameters:

<?xml version="1.0" encoding="UTF-8"?><server xmlns="urn:jboss:domain:1.1">
    <extensions>
        <extension/>
        <extension/>

instead of

<?xml version="1.0" encoding="UTF-8"?><server xmlns="urn:jboss:domain:1.1">
    <extensions>
        <extension module="org.jboss.as.clustering.infinispan"/>
        <extension module="org.jboss.as.configadmin"/>

Why?
How can i Make it copy everything?

XSLT transformation is done by Maven XML plugin.
The whole template:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
            xmlns:ds="urn:jboss:domain:datasources:1.0"
            xmlns="urn:jboss:domain:1.1"
            version="1.0">
    <xsl:output method="xml" indent="yes"/>

<xsl:template match="*|@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="*|@*|node()"/>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T02:06:56+00:00Added an answer on May 30, 2026 at 2:06 am

    Your template appears to be working correctly.

    I modified it and the XML to show that is working:

    <?xml version="1.0" encoding="UTF-8"?>
    <server xmlns="urn:jboss:domain:1.1">
      <extensions>
        <extension module="org.jboss.as.clustering.infinispan"/>
        <extension module="org.jboss.as.configadmin"/>
      </extensions>
    </server>
    

    Run with this XSL:

    <?xml version="1.0" encoding="UTF-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                    xmlns:ds="urn:jboss:domain:datasources:1.0"
                    xmlns:so="urn:jboss:domain:1.1"
                    version="1.0">
      <xsl:output method="xml" indent="yes"/>
    
      <xsl:template match="*|@*|node()">
        <xsl:copy>
          <xsl:apply-templates select="*|@*|node()"/>
        </xsl:copy>
      </xsl:template>
      <xsl:template match="so:extension">
        <xsl:copy>
        <xsl:attribute name="testing">just for fun!!</xsl:attribute>
        <xsl:copy-of select="@*|node()"/>
        </xsl:copy>
      </xsl:template>
    </xsl:stylesheet>
    

    Produces:

    <?xml version="1.0"?>
    <server xmlns="urn:jboss:domain:1.1">
      <extensions>
        <extension testing="just for fun!!" module="org.jboss.as.clustering.infinispan"/>
        <extension testing="just for fun!!" module="org.jboss.as.configadmin"/>
      </extensions>
    </server>
    

    Here’s the output run with your original XSL:

    <?xml version="1.0"?>
    <server xmlns="urn:jboss:domain:1.1">
      <extensions>
        <extension module="org.jboss.as.clustering.infinispan"/>
        <extension module="org.jboss.as.configadmin"/>
      </extensions>
    </server>
    

    I downloaded the full JBoss standalone.xml, ran your XSL, and here’s the diff of the input and output XML:

    so zacharyyoung$ xsltproc so.xsl so.xml > output.xml
    so zacharyyoung$ diff so.xml output.xml
    1,2c1
    < <?xml version='1.0' encoding='UTF-8'?>
    < 
    ---
    > <?xml version="1.0"?>
    
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