Question

Are there any way to predict some number of the Random class without going through a loop of rnd.NextDouble()?

i am using this code now:

Random rnd = new Random(SOME_STATIC_SEED);

//I need to get the 1000000'th random number:
for (ulong i = 0; i < 1000000; i++) 
//I need to avoid this loop and get the result in a linear time!
{
      rnd.NextDouble();
}
double iNeedThisNumber = rnd.NextDouble();

How can i get it without the loop? i need the same exact number given using the algorithm of System.Random class of .Net!

---

Allegedly solved:

This is my code!!

public static ulong GetNumberFromSequence(int seq) 
{ 
    Random rnd = new Random(seq); 
    return (ulong)(rnd.NextDouble() * 99999999999999) ^ (ulong)seq; 
}

Answer 1

See if this works for you

Use the seed for the desired index in the random-number generator, and then pick the first generated number.

Random rnd = new Random(required_index_as_seed).Next();
double iNeedThisNumber = rnd.NextDouble();