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Home/ Questions/Q 3786230
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:39:03+00:00 2026-05-19T11:39:03+00:00

As a kind of factory-method setup I want to register functors which each create

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As a kind of factory-method setup I want to register functors which each create objects of a different type, but meet a common interface – i.e all create objects subclassing a core class.

Say I have something like:

template <class T> struct FactoryMethod
{
 X* create();
}

I cannot have (IIRC) std::map<std::string,FactoryMethod*> because each FactoryMethod template specialization is a separate type. But I could do:

struct IFactoryMethod
{
 virtual X* create()=0;
};
template <class T> struct FactoryMethod : public IFactoryMethod
{
 virtual X* create();
};
std::map<std::string,IFactoryMethod*> factories;

Right? I am not aware standard STL has a way to make this neater though I guess boost does – however we don’t use boost right now and I am interested anyway.

The idea is then factories can be looked up based on type-name (read from XML for instance) to create the right type.

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:39:04+00:00Added an answer on May 19, 2026 at 11:39 am

    This is known as type erasure and is a fairly common idiom- although your map could of course be made of ownership-enforcing pointers and you could also use a virtual destructor like most sane people.

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