Question

As a learning exercise, I am creating a program that converts characters entered through argv[1] to integers. The program then finds the digital mean of the integers.

For example: abc would be 123, and 1+2+3 = 6, six being the digital mean. The first part of the program works, but I am unable to properly code the portion that finds the digital mean.

Output from word abc should be 123 6; instead it is 123 150.

---

EDIT: Solved!

#include <stdio.h>
#include <strings.h>

int main(int argc, char *argv[])
{
    char stra[27], strb[0];
    int str_num, str_len;
    int final = 0;

    if (argv[1][0] < 'a')
    {
        printf("!Argument missing!");
        return 0;
    }

    strcpy(stra, argv[1]);
    str_len = strlen(stra);

    for (str_num = 0; str_num < str_len; str_num++)
    {
        if (stra[str_num] <= 'z' && stra[str_num] >= 'a')
        {
            strb[str_num] = (stra[str_num] - 'a' + 1) % 9 + '0';
            if (strb[str_num] == '0')
            {
                strb[str_num] = '9';
            }
        }
        else
        {
            printf("%s !Please use only the lower case!", stra);
            return 0;
        }
    }

    for (str_num = 0; str_num < str_len; str_num++)
    {
        final += strb[str_num] - '0';
    }

    printf("%s %i", strb, final);
    return 0;
}

Answer 1

#include <stdio.h>
#include <strings.h>
int main(int argc, char *argv[])
{
    char *stra;
    char *strb;
    int str_num;
    int str_len;
    int final;
    final = 0;
    if ( (argc >= 2 && argv[1][0] < 'a') || (argc <= 1))
    {
        printf("!Argument missing!");
        return 0;
    }
    str_len = strlen(argv[1]);

    strb = (char*) malloc((str_len+1)*sizeof(char));

    for (str_num = 0; str_num < str_len; str_num++)
    {
        if (argv[1][str_num] <= 'z' && argv[1][str_num] >= 'a')
    {
        strb[str_num] = (argv[1][str_num] - 'a'+1) % 9 + '0'; //to get string with numbers from 1 to 9
        }
        else
        {
            printf("%s !Please use only the lower case!",argv[1]);
            return 0;
        }
    }
    strb[str_len] = '\0' // put the end char of the string : mandatory to print it.
    for (str_num = 0; str_num < str_len; str_num++)
    {
        final += strb[str_num] - '0';  // count the sum of the numbers from 1 to 9 ?
    }
    printf("%s %i",strb,final);
    free(strb);
    return 0;
}