Question

As an example, this URL:

http://example.com/get_image?type=1

should return a response with a image/gif MIME type. I have two static .gif images,
and if type is 1, it should return ok.gif, else return error.gif. How to do that in flask?

Answer 1

You use something like

from flask import send_file

@app.route('/get_image')
def get_image():
    if request.args.get('type') == '1':
       filename = 'ok.gif'
    else:
       filename = 'error.gif'
    return send_file(filename, mimetype='image/gif')

to send back ok.gif or error.gif, depending on the type query parameter. See the documentation for the send_file function and the request object for more information.