Question

As far as I can tell, this looks like it should work.

The first two elements are set to 1 (I am ignoring the first 0). The for loop is supposed to loop through the array, and since the fibonacci numbers are equal to the sum of the two preceeding numbers, I want to add them, then display them.

The output is all 2s, and I am not quite sure why.

Note: I am not looking directly for the answer, but a way that I can figure this out myself.

//Fibonacci sequence
#include <stdio.h>

int main(void) {
        int fib_numbers[40] = {1, 1}, i;


        for(i = 1; i < 40; i++) {
                fib_numbers[i] = fib_numbers[i] + fib_numbers[i - 1];
                printf("\t%d\n", fib_numbers[i]);
            }

        return 0;
}

Answer 1

After the first step, the erray element is 0 (non initialized, but 0 in this case). What about
fib[i+1] = fib[i]+fib[i-1]; printf (“%d\n”,fib[i+1])?
And of course fib must have size of 41 instead of 40.