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Home/ Questions/Q 6784449
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:59:46+00:00 2026-05-26T16:59:46+00:00

as part of a HTML form I am creating I would like to have

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as part of a HTML form I am creating I would like to have a dropdown list which will list all the usernames in my database.

I thought the following code would do the trick but the dropdown list is empty – could someone assist me in what i’m doing wrong? Thanks.

<tr>
<td>Owner</td>
<td>
<select name="owner">
<?php 

$sql = mysqli_query($connection, "SELECT username FROM users");

while ($row = $sql->fetch_assoc()){

?>
<option value="owner1"><?php echo $row['username']; ?></option>

<?php
// close while loop 
}
?>
</td>
</tr>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:59:47+00:00Added an answer on May 26, 2026 at 4:59 pm

    My guess is that you have a problem since you don’t close your select-tag after the loop. Consider separating your database-related code from the markup, it will help you to spot such mistakes easily

    <?php
    ...
    // SQL part
    $sql = mysqli_query($connection, "SELECT username FROM users");
    $data = $sql->fetch_all(MYSQLI_ASSOC);
    
    // HTML part
    ?>
    <tr>
      <td>Owner</td>
      <td>
        <select name="owner">
          <option value=""></option>
          <?php (foreach $data as $row): ?>
          <option value="<?= htmlspecialchars($row['id']) ?>">
            <?= htmlspecialchars($row['username']) ?>
          </option>
          <?php endforeach ?>
        </select>
      </td>
    </tr>
    

    Note that you have to either give the each value attribute a unique value or omit this attribute altogether. I added the row id as such value.

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