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Home/ Questions/Q 1020855
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:13:16+00:00 2026-05-16T11:13:16+00:00

As part of a large python program I have the following code: for arg

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As part of a large python program I have the following code:

for arg in sys.argv:
    if "name=" in arg:
            name = arg[5:]
            print(name)
    elif "uname=" in arg:
            uname = arg[6:]
            print(uname)
    elif "password=" in arg:
            password = arg[9:]
            print(password)
    elif "bday=" in arg:
            bday = arg[5:]
            print(bday)
    else:
            pass

The program expects something like:

python prog.py "name=Kevin" "uname=kevin" "password=something" "bday=01/01/01"

When I try to use “uname” later, the program fails, claiming “uname is not defined”
I added the “print()” lines to try and debug and the “print(uname)” always shows “=kevin” regardless of the index number I put there (here “6:”). The other statements seem to work fine. Is this a bug in python? I am very confused.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-16T11:13:17+00:00Added an answer on May 16, 2026 at 11:13 am

    The elif “uname=” is never run because the string “name=” is in “uname=”. Essentially, you are overwriting your name variable.

    >>> "name=" in "uname="
    True
    

    You could reorder your ifs so that so that the uname occurs before the name one.

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