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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:40:16+00:00 2026-05-13T21:40:16+00:00

As per my understanding a lock is not released until the runtime completes the

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As per my understanding a lock is not released until the runtime completes the code block of the lock(obj) ( because when the block completes it calls Monitor.Exit(obj).

With this understanding i am not able to understand the reason behind the behaviour of the following code :

private static string obj = "";
        private static void RecurseSome(int number)
        {
            Console.WriteLine(number);
            lock (obj)
            {
                RecurseSome(++number);
            }
        }

//Call: RecurseSome(0)

//Output: 0 1 2 3...... stack overflow exception

There must be some concept that i am missing. Please help.

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:40:17+00:00Added an answer on May 13, 2026 at 9:40 pm

    A lock knows which thread locked it. If the same thread comes again it just increments a counter and does not block.

    So, in the recursion, the second call also goes in – and the lock internally increases the lock counter – because it is the same thread (which already holds the lock).

    ms-help://MS.VSCC.v90/MS.MSDNQTR.v90.en/dv_csref/html/656da1a4-707e-4ef6-9c6e-6d13b646af42.htm

    Or MSDN: http://msdn.microsoft.com/en-us/library/c5kehkcz.aspx

    states:

    The lock keyword ensures that one thread does not enter a critical section of code while another thread is in the critical section. If another thread tries to enter a locked code, it will wait, block, until the object is released.

    Note the thread references and the emphasis on “ANOTHER” thread.

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