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Home/ Questions/Q 8118875
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T04:37:44+00:00 2026-06-06T04:37:44+00:00

As per Scott Meyers, to prevent repetition of code in the const version of

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As per Scott Meyers, to prevent repetition of code in the const version of a getter and the non-const version of a getter, call the const version of the method from the non-const version: static_cast<const A&>(*this).Methodology(); however, in accidental usage due to an overzealous Visual Assist X Intellisense I typed: const_cast<const A&>(*this).Methodology(); and it worked just fine.

What are any and all differences in this case with using a particular cast?

IDE in use: Visual Studio 2010.

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  1. Editorial Team
    Editorial Team
    2026-06-06T04:37:46+00:00Added an answer on June 6, 2026 at 4:37 am

    Assuming that the type of this is A*, there is no difference.

    In general const_cast can cast aways the const specifier (from any level of indirection or template parameter)

    static_cast<> can cast a type to another if the target type is in the source’s type hierarchy.

    They cannot do each other’s work.

    The reason they both worked in your case is because you have introduced const-ness, as opposed to having taken it away (calling from the non-const version of the function the type of this is A*, no const). You could just as well have written

    const A& tmp = *this;
    tmp.Methodology();
    

    and it would have worked without the need for any casting. The casting is used for convenience and terseness to not have to introduce a new variable.

    Note: you can use static_cast<> here as you know that you are casting to the right type. In other cases (when you cannot be sure) you need to use dynamic_cast<> that does a runtime type check to ensure the conversion is valid

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