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As the reverse of i.toString(32) is there a better (i.e. working) method to use instead of
i = Integer.parseInt(string, 32)
to create a BigInteger, as the string I want to pass is 11 ‘characters’ long? (D4KJI9QLC3L) gives me
java.lang.NumberFormatException: For input string: "D4KJI9QLC3L"
Parameters:{val=14800099002200181, str=D4KJI9QLC3L}
If I add .toBigInteger() to the end it deos not seem to help at all.
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