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Home/ Questions/Q 7787329
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T20:37:48+00:00 2026-06-01T20:37:48+00:00

As the title says I am loading a flash in my webpage and when

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As the title says I am loading a flash in my webpage and when I call LoadVars() it crashes the web page.
Here is my code:

Flash

lv = new LoadVars();   
lv.onLoad = onLoadCallBack;  
lv.load("php/flash_getitems.php");

function onLoadCallBack(succes){
    if(succes){
        t = lv[this.totalItems];
        for(i = 1; i<= t; i++){
            key = this.itemName + "" + i;
            itemList.addItemAt(i, key);
        }
    }

}
stop();  

php

INCLUDE 'connector.php';

$query = mysql_query("SELECT * FROM shop");
$totalrows = mysql_num_rows($query);
echo "&totalItems=$totalrows";

    while($row = mysql_fetch_assoc($query)){
        $id = $row['id'];
        $item = $row['item'];
        $desc = $row['description'];
        $price = $row['price']; 
        echo "&itemName$id=$item";
        echo "&price$id=$price";
        echo "&desc$id=$desc";
    }

This will return values like this
&itemName1=First Item&price1=100&desc1=description
and so on so forth with the higher id’s

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T20:37:50+00:00Added an answer on June 1, 2026 at 8:37 pm

    It looks to me like your parsing function has a couple of syntax errors.

    See if this works any better:

    function onLoadCallBack(success){
        if(success){
            for(var i:Number = 1; i<= lv.totalItems; i++)
                itemList.addItemAt(i, lv["itemName"+i]);
        }
    }
    

    lv["itemName"+i] will evaluate to lv.itemName1, etc. You tried to access undefined variables, which causes a null reference error.

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