As you know sendmsg has this declaration:
int sendmsg(int s, const struct msghdr *msg, int flags);
and msghdr structure has this form:
struct msghdr {
void * msg_name; /* optional address */
socklen_t msg_namelen; /* size of address */
struct iovec * msg_iov; /* scatter/gather array */
size_t msg_iovlen; /* # elements in msg_iov */
void * msg_control; /* ancillary data, see below */
socklen_t msg_controllen; /* ancillary data buffer len */
int msg_flags; /* flags on received message */
};
As you see msghdr has an array of buffer, iovec and has buffer count msg_iovlen. What I wonder is that how sendmsg sends these buffers. Does it concatenate all buffers and send or does it send in a for loop?
The manpage speaks of a message (singular) and multiple elements (plural):
For a stream socket, it wouldn’t matter either way. Any data you send will just end up as one long stream of data on the other side.
For datagram or message sockets, I can see why a bit more clarity would be helpful. But it appears that you send just one datagram or message with a single
sndmsgcall; not one per buffer element.I actually went digging in the Linux source code out of curiosity and to get a better feeling about this answer. It looks like
send, andsendtoare just wrappers forsendmsgin Linux, that build thestruct msghdrfor you. And in fact, the UDPsendmsgimplementation makes room for one UDP header persendmsgcall.If performance is what you’re worried about, it doesn’t look like you’ll benefit from
sendmsgif you pass in just a singleiovec. If you’re concatenating buffers in user-space, though, this could potentially win you some.It’s a bit similar to
writev, with the added benefit that you can specify a destination address for use with connectionless sockets like UDP. You can also add ancillary data, if you’re into that sort of thing. (Commonly used to send file descriptors across UNIX domain sockets.)