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Home/ Questions/Q 564079
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:43:42+00:00 2026-05-13T12:43:42+00:00

Assume a Linux binary foobar which has two different modes of operation: Mode A:

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Assume a Linux binary foobar which has two different modes of operation:

  • Mode A: A well-behaved mode in which syscalls a, b and c are used.
  • Mode B: A things-gone-wrong mode in which syscalls a, b, c and d are used.

Syscalls a, b and c are harmless, whereas syscall d is potentially dangerous and could cause instability to the machine.

Assume further that which of the two modes the application runs is random: the application runs in mode A with probability 95 % and in mode B with probability 5 %. The application comes without source code so it cannot be modified, only run as-is.

I want to make sure that the application cannot execute syscall d. When executing syscall d the result should be either a NOOP or an immediate termination of the application.

How do I achieve that in a Linux environment?

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:43:43+00:00Added an answer on May 13, 2026 at 12:43 pm

    Is the application linked statically?

    If not, you may override some symbols, for example, let’s redefine socket:

    int socket(int domain, int type, int protocol)
    {
            write(1,"Error\n",6);
            return -1;
    }
    

    Then build a shared library:

    gcc -fPIC -shared test.c -o libtest.so
    

    Let’s run:

    nc -l -p 6000
    

    Ok.

    And now:

    $ LD_PRELOAD=./libtest.so nc -l -p 6000
    Error
    Can't get socket
    

    What happens when you run with variable LD_PRELOAD=./libtest.so? It overrides with symbols defined in libtest.so over those defined in the C library.

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