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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T04:17:00+00:00 2026-06-11T04:17:00+00:00

Assume a machine has a throughput of 70 ops/s. Say we have an algorithm

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Assume a machine has a throughput of 70 ops/s. Say we have an algorithm with time complexity
T(n) = 2n^2 + 120

Determine how many hours will it take the machine to execute said algorithm for an input of size n = 8.


Is this correct?

T(n) = 2n^2 + 120

T(8) = 2(8)^2 + 120
= 248 * 70 * 1000

Please help.

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  1. Editorial Team
    Editorial Team
    2026-06-11T04:17:01+00:00Added an answer on June 11, 2026 at 4:17 am

    A few hints:

    • If your program does 70 operations, how many seconds does it take?

    • How many seconds in an hour? (How many seconds in a minute, and how many minutes in an hour?)

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