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Home/ Questions/Q 972001
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:03:12+00:00 2026-05-16T03:03:12+00:00

Assume I have a muti-level hash: $class->{‘key1’}->{‘key2’}->{$key3}->{‘string’}->{$key5}, where $class->{‘key1’}->{‘key2’}->{$key3}->{‘string’}->{$key5} equals to some integer number.

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Assume I have a muti-level hash:

$class->{‘key1’}->{‘key2’}->{$key3}->{‘string’}->{$key5},
where $class->{‘key1’}->{‘key2’}->{$key3}->{‘string’}->{$key5}
equals to some integer number.
$key3 can be class name like "music", "english"…
$key5 can be student name like "mary", "luke"…

Will the following operation release all the memory under level $key3="music"?
i.e. will the memory assigned to $key5 be released?

$current_class = $class->{‘key1’}->{‘key2’}->{"music"};
$current_class = undef;

Update:

thanks both. My understanding between delete and undef is: delete will remove the entry of key='music'

so $class->{'key1'}->{'key2'}->{"music"} will not exist. while undef will set value of $class->{'key1'}->{'key2'}->{"music"} as undef. but entry of key='music' is still there but the value of it will be undef so $class->{'key1'}->{'key2'}->{"music"} = undef.

so I should delete the entry, is it correct?

but do you mean

undef $class->{‘key1’}->{‘key2’}->{"music"};

and

$class->{‘key1’}->{‘key2’}->{"music"} = undef;

are different?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:03:13+00:00Added an answer on May 16, 2026 at 3:03 am

    Perl has reference counting garbage collector.

    $ cat test.pl

    #!/usr/bin/perl
    use strict;
    package Cat;
    sub new { my ($class,$name) = @_; print "cat $name here\n"; bless \$name, $class; }
    sub DESTROY { my $self = shift; print "  cat $$self gone\n"; }
    
    package main;
    my $ref->{aaa}->{bbb}->{ccc} = new Cat 'Alfred';
    print  "111111\n";
    $ref->{aaa} = 'qweqwe';
    print  "222222\n";
    

    $ ./test.pl

    cat Alfred here
    111111
      cat Alfred gone
    222222
    
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