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Home/ Questions/Q 5933997
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:03:07+00:00 2026-05-22T15:03:07+00:00

Assume I have an array $arr. It’s possible that it has an element with

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Assume I have an array $arr. It’s possible that it has an element with a key named ‘music’ ($arr[‘music’]), and I want to test whether that value equals “classical”:

if($arr['music'] === 'classical'){
    //do something cool
}

However, it’s possible that $arr does not have a value with the key ‘music’. In order to avoid a PHP error, I therefore do the following:

if($arr['music']){
    if($arr['music'] === 'classical'){
        //do something cool
    }
}

This seems totally ridiculous. In MY opinion, if $arr[‘music’] doesn’t exist, then it DEFINITELY doesn’t equal ‘classical’. Is there a way to avoid first testing whether a key exists before testing it’s value?

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:03:08+00:00Added an answer on May 22, 2026 at 3:03 pm

    If the key does not exist it will throw an error (or a warning).
    So in order for that to happen, you have to check if it does exist.
    Here are two ways to do that:

    You can check it using isset() (which will be false if $arr['music'] == null):

    if(isset($arr['music']) && $arr['music'] === 'classical'){ 
        //do something cool
    }
    

    Or use array_key_exists():

    if(array_key_exists('music', $arr) && $arr['music'] === 'classical'){
        //do something cool
    }
    
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