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Home/ Questions/Q 266825
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T23:28:34+00:00 2026-05-11T23:28:34+00:00

Assume that I have this piece of code: @interface Foo : NSObject { Bar

  • 0

Assume that I have this piece of code:

@interface Foo : NSObject {
    Bar *bar;
}

@property (retain, nonatomic) Bar *bar;

@end

When using this field/property, is there any difference between lines:

[self.bar doStuff];

and

[bar doStuff];

?

When doing assignment, property method will perform correct retaining, but what about the read access to the property, as described above? Is there any difference?

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  1. Editorial Team
    Editorial Team
    2026-05-11T23:28:34+00:00Added an answer on May 11, 2026 at 11:28 pm

    There is a big difference.
    [self.bar doStuff] is equivalent to [[self bar] doStuff]

    [bar doStuff] is equivalent to [self->bar doStuff]

    The former uses the accessor method, the latter just accesses the instance variable bar directly.

    If you use the @synthesize directive on your bar property, the compiler will generate two methods for you:

    - (void)setBar:(Bar*)b;
    - (Bar*)bar;
    

    Also note, that the compiler generated setter method is retaining your Bar instance as you told it in the @property declaration.

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