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Home/ Questions/Q 503713
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:25:19+00:00 2026-05-13T06:25:19+00:00

Assume this Java code: public class A { public A(String g) { x +=

  • 0

Assume this Java code:

public class A {
   public A(String g) {
      x += g.length();
   }

   private int x = 0;
}

If I create an instance of A, like this:

A a = new A("geo");

after this call, the value of x will be 3. What am I doing wrong in my Scala code?

class A(val g:String) {
  x += g.length
  var x:Int = 0
}

object x extends Application {
  val x = new A("geo")
  println(x.x)
}

This prints 0. I assumed that when the compiler reaches the var x:Int = 0, the body of the main constructor has ended. Am I wrong? How else could you declare instance variables in Scala ( assuming I don’t want them in my constructor ) ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:25:20+00:00Added an answer on May 13, 2026 at 6:25 am

    Keep in mind that your code translates into something similar (but not exactly) to this:

    public class A {
    
      private final String g;
      private int x;
    
      public A(String g) {
        this.g = g;
        x_$eq(x() + g.length());
        x = 0;
      }
    
      public void x_$eq(int arg0) {
        x = arg0;
      }
    
      public int x() {
        return x;
      }
    
      public String g() {
        return g;
      }
    }
    

    But vars defined in (non-constructor) methods get translated into actual local variables.

    Not sure if this explains the reasoning so much as highlights one of the differences.


    EDIT – Changed “translation” from scala to java for clarity and ability to more accurately represent what is happening.

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