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Asked: 2026-05-11T13:21:57+00:00

Assume we have: $a = @(1, @(2, @(3))) I would like to flatten $a

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Assume we have:

$a = @(1, @(2, @(3)))

I would like to flatten $a to get @(1, 2, 3).

I have found one solution:

@($a | % {$_}).count

But maybe there is a more elegant way?

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1 Answer

  1. Piping is the correct way to flatten nested structures, so I’m not sure what would be more ‘elegant’. Yes, the syntax is a bit line-noisy looking, but frankly quite serviceable.

    2020 Edit

    The recommended syntax these days is to expand % to ForEach-Object. A bit more verbose but definitely more readable:

    @($a | ForEach-Object {$_}).count
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