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Home/ Questions/Q 8439563
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T08:01:44+00:00 2026-06-10T08:01:44+00:00

Assume you have the following code: function name() { $(this).css(‘background’, ‘red’); } $(‘selector1’).click(name); $(‘selector2’).click(function

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Assume you have the following code:

function name() {
    $(this).css('background', 'red');
}

$('selector1').click(name);

$('selector2').click(function () {
    name.call($(this).parent());
});

Now, when the function is called by clicking on ‘selector1’ this is an HTML object and $(this) a jQuery object, but if the function is called by clicking on ‘selector2’ this is already a jQuery object so what is $(this)?

I know I could do something like name.call($(this).parent()[0]); to get an HTML object, but my question is what happens when you do something like $($(this)) or $($('selector'))? What is the result of that and, most impotently, is there any harm in using such a construct?

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  1. Editorial Team
    Editorial Team
    2026-06-10T08:01:45+00:00Added an answer on June 10, 2026 at 8:01 am

    $(this) when this is already a jQuery object creates a copy of the jQuery object.

    From the jQuery docs:

    Cloning jQuery Objects

    When a jQuery object is passed to the $() function, a clone of the object is created.
    This new jQuery object references the same DOM elements as the initial one.

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