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Home/ Questions/Q 3281168
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:47:10+00:00 2026-05-17T19:47:10+00:00

Assuming I have a string $str = "abc*efg*hij*"; and an array $arr = array("123","456","789");

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Assuming I have a string

$str = "abc*efg*hij*";

and an array

$arr = array("123","456","789");

Now I want to replace the *s in $str with the elements in $arr according to the positions.The first * replaced with $arr[0],the second replaced with $arr[1] etc.I check the function str_replace,though it accepts arrays as parameters but I found it did not work.And I cannot just use

$newstr = "abc{$arr[0]}efg{$arr[1]}hij{$arr[2]}"

because the real $str may be quite a long string with lots of *.Any good ideas?Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:47:10+00:00Added an answer on May 17, 2026 at 7:47 pm

    If * is your only format character, try converting * to %s (also escape existing % to %%), and then using vsprintf(), which takes an array of values to pass in as format parameters:

    $str = str_replace(array('%', '*'), array('%%', '%s'), $str);
    $newstr = vsprintf($str, $arr);
    echo $newstr;
    

    Output:

    abc123efg456hij789
    

    Note that if you have more array elements than asterisks, the extra elements at the end simply won’t appear in the string. If you have more asterisks than array elements, vsprintf() will emit a too-few-arguments warning and return false.

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