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Home/ Questions/Q 9038013
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T09:23:01+00:00 2026-06-16T09:23:01+00:00

Assuming I have this code (simplified from Synopsis ) {-# LANGUAGE QuasiQuotes, TemplateHaskell, TypeFamilies,

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Assuming I have this code (simplified from “Synopsis”)

{-# LANGUAGE QuasiQuotes, TemplateHaskell, TypeFamilies, OverloadedStrings #-}
{-# LANGUAGE GADTs, FlexibleContexts #-}
import Database.Persist
import Database.Persist.Sqlite
import Database.Persist.TH
import Control.Monad.IO.Class (liftIO)
import Control.Monad.Trans.Resource (runResourceT)

share [mkPersist sqlSettings, mkMigrate "migrateAll"] [persist|
Person
  name String
|]

main :: IO ()
main = runResourceT $ withSqliteConn ":memory:" $ runSqlConn $ do
  runMigration migrateAll

  johnID <- insert $ Person "John Doe"
  janeID <- insert $ Person "Jane Doe"

  liftIO $ print johnID
  liftIO $ print janeID

  return ()

input = [Person "John Doe", Person "Jane Doe"]

How would I insert the list input and in turn receive a list of IDs?

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  1. Editorial Team
    Editorial Team
    2026-06-16T09:23:03+00:00Added an answer on June 16, 2026 at 9:23 am

    You can use forM function into runSqlConn block. For example:

    main :: IO ()
    main = runResourceT $ withSqliteConn ":memory:" $ runSqlConn $ do
        runMigration migrateAll
    
        ids <- forM input insert
        liftIO $ print ids
    
      where
        input = [Person "John Doe", Person "Jane Doe"]
    
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