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Home/ Questions/Q 8918001
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T05:38:30+00:00 2026-06-15T05:38:30+00:00

assuming the following simple code: for(int i=0; i < 1000; i++) { cout <<

  • 0

assuming the following simple code:

for(int i=0; i < 1000; i++)
{
  cout << "Outer i: " << i << endl;
  for(int i=0; i < 12; i++)
  {
    cout << "Inner i:" << i << endl;
  }
}

Works very nice. The same variable name in both loops used and the output is fine.

Do I understand it right that both variables are created on stack, and when the outer loop comes to the new inner loop, a new “namespace” (maybe the wrong name..) is created? But why is it overwritten? If I choose another name for the variable in inner loop I can also access the i from outer loop.

A bit confused I am.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T05:38:31+00:00Added an answer on June 15, 2026 at 5:38 am

    “Namespace” is kinda close.. but it is more about scope. The inner i hides/surpresses the outer i. You could think of another example:

    { 
     int i=0; //outer scope i.
     {
       int i =0; //this hides the outer scope i.. I can't use outer i here
    
     }
      i =1 ; //inner i is out of scope.. outer i is set to 1
    }
    
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