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Asked: May 11, 20262026-05-11T14:17:56+00:00 2026-05-11T14:17:56+00:00

Assuming this is a singleton implementation: Am I guaranteed that this will only call

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Assuming this is a ‘singleton’ implementation: Am I guaranteed that this will only call productCatalogLoader.load() once, and also that no nullpointers can happen ? Any way to make this simpler ?

private final ReentrantReadWriteLock lock = new ReentrantReadWriteLock(); private ProductCatalog productCatalog;  public ProductCatalog get() {         if (this.productCatalog == null) {             reload();          }         return this.productCatalog; }                                                           public void reload() {      lock.writeLock().lock();     try {         if (this.productCatalog != null) return;         this.productCatalog = productCatalogLoader.load();     } finally {         lock.writeLock().unlock();     } } 

}

Edit: This was a modestly successful attempt reduce much more complex code to a simple question sample. Several people caught on to the fact that my singleton was too complex 😉 (Actually there’s also a quartz timer calling reload, but the ‘reload’ implementation is a bit different IRL). I got the answer I needed anyway, broken double checked locking.

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  1. 2026-05-11T14:17:57+00:00Added an answer on May 11, 2026 at 2:17 pm

    this looks like broken double checked locking. the problem is this.productCatalog can be assigned before the object is fully contructed.

    say we have

    var foo = new ProductCatalog(); foo.blah = 'blah blah'; this.productCatalog = foo; 

    the can be reordered as

    var foo = new ProductCatalog(); this.productCatalog = foo; foo.blah = 'blah blah'; 
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