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Home/ Questions/Q 6564071
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:55:16+00:00 2026-05-25T13:55:16+00:00

Assuming we have a simple struct like: typedef struct { int d1; int d2;

  • 0

Assuming we have a simple struct like:

typedef struct
{
    int d1;
    int d2;
    float f1;
}Type;

Which is the correct when allocate memory for a new instance of it:

This:

// sizeof *t == sizeof(Type) ( gcc prints 12 bytes)
Type *t = malloc(sizeof *t); 

or:

// sizeof pointer always == 4 (in my case also on gcc)
Type *t = malloc(sizeof(t)); 

Which is the correct?

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:55:17+00:00Added an answer on May 25, 2026 at 1:55 pm
    Type *t = malloc(sizeof *t); 
    

    This is the correct way to allocate the amount of memory needed for a new instance.

    Type *t = malloc(sizeof (t)); 
    

    This will only allocate enough storage for a pointer, not an instance.

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