Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6001963
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T00:54:35+00:00 2026-05-23T00:54:35+00:00

At my company we have the code convention to write $foo . $bar (with

  • 0

At my company we have the code convention to write $foo . $bar (with whitespaces). Because I couldn’t get familiar with that (I don’t want to discuss 😛 ), I wrote the following vim-replace-function:

:%s/\(\w\|\]\|'\|\"\)\s\?\.\s\?\('\|\$\|\"\|(\)/\1 \. \2/eg

..which matches everything I needed so far. But now I also have String which I don’t want to replace.

So how can I ignore Strings like “foo.bar” or ‘foo.bar’, but not $foo.$bar ?

Update: I would also be happy with a completely scripted function. I just wonder if there is no other way than temporarily remove all php-strings. Re-calculating the actual replacement-positions would be a mess, no?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T00:54:36+00:00Added an answer on May 23, 2026 at 12:54 am

    You can make use of syntax highlighting here:

    :%s/\(\w\|\]\|'\|\"\)\s\?\.\s\?\('\|\$\|\"\|(\)/\=synIDattr(synID(line('.'),col('.'), 0),'name')!~?'phpString\(Single\|Double\)'?submatch(1) . ' . ' . submatch(2):submatch(1).'.'.submatch(2)/eg
    

    Basically that means, if the string below the cursor is not of Syntax type phpStringSingle and not phpStringDouble, then replace by adding a ‘ . ‘ between each capturing group, else leave it as it was.

    Read more about it at:

    :h sub-replace-expression
    :h expr1
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

For work I have to code with an external company's API to deal with
My company recently purchased TFS and I have started looking into the code analysis
I have a small website for a company that have 40-50 product. The site
At every company I have worked at, I have found that people are still
The context: We’re a small company that does not have an Exchange Server (or
I have a foxpro database that we are trying to write to using MS
I have a helpdesk package for our company that I am attempting to integrate
I have the following code: Tag.find_all_by_company_id(4).each.collect{|tag| tag.name }.join(,) (Essentially I'm trying to build a
I have the following code: <%= select_tag :role, options_for_select(Project::COMPANY_ROLES.concat(['Other...']), @relationship.role) %> For some reason
I have the following line of code. <%= Html.Encode(string.Join(, , item.company1.companies.Select(x => x.company_name).ToArray())) %>

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.