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Home/ Questions/Q 6533111
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:05:09+00:00 2026-05-25T10:05:09+00:00

Atm i have sth like that: template<int n> struct Pow { enum{val= Pow<n-1>::val<<1}; };

  • 0

Atm i have sth like that:

template<int n>
struct Pow
{
  enum{val= Pow<n-1>::val<<1};
};
template<>
struct Pow<0>{
    enum{val =1};
};

I can acess data like Pow<30>::val. It’s good but i want do like this

   int main()
    {
    Pow<30>::val;

and then use variable to
access all of value <0,30>
I knew that i can use array and dynamic programming but can i do that in this way?
Sorry for English.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:05:10+00:00Added an answer on May 25, 2026 at 10:05 am

    Using C++0x variadic templates:

    template<int... Indices>
    struct powers {
        static const int value[sizeof...(Indices)];
    
        typedef powers<Indices..., sizeof...(Indices)> next;
    };
    
    template<int... Indices>
    const int powers<Indices...>::value[sizeof...(Indices)] = { Pow<Indices>::val... };
    
    template<int N>
    struct build_powers {
        typedef typename build_powers<N - 1>::type::next type;
    };
    
    template<>
    struct build_powers<1> {
        typedef powers<0> type;
    };
    

    and then:

    int
    main()
    {
        // we want [0..30] inclusive so pass 31 as exclusive upper limit
        typedef build_powers<31>::type power_type;
        // 0..30 is 31 powers in all
        typedef const int array_type[31];
    
        array_type& ref = power_type::value;
        // ref[0] .. ref[30] are the values of Pow<0>::val .. Pow<30>::val
    }
    

    So that’s with using an array but without dynamic initialization. Since you want the result as a variable and not for TMP I feel this is adequate.

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