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Home/ Questions/Q 1058339
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:00:44+00:00 2026-05-16T18:00:44+00:00

Background: In Ruby I have a 2d array like the following: count[[english_word, french_word]] =

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Background: In Ruby I have a 2d array like the following:

count[[english_word, french_word]] = ...
pp count
{["my", "une"]=>0.0,
 ["my", "voiture"]=>0.2,
 ["red", "maison"]=>0.9,
...
}

(The reason I did this rather than count[english_word][french_word] was I wasn’t sure how to get around the Undef errors, and I saw this syntax suggested on Stack Overflow)

I’ve filled the data structure with a pair of nested loops using a english_vocab and french_vocab arrays of all words.

Question: I would like to be able to get the maximum of a given English word.

english_word = 'foo'
max_count = 0
french_vocab.each do |french_word|
   count = count[[english_word, french_word]]
   if count > max_count
       max_count = count
   end
end

I can do this with a simple nested for loop, but I’m wondering if there’s a nicer Ruby-ish way of doing the same thing?

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:00:45+00:00Added an answer on May 16, 2026 at 6:00 pm

    I think it’s much easier than you’re thinking it is.

    hash = {
      ["my", "une"]=>0.0,
      ["my", "voiture"]=>0.2,
      ["red", "maison"]=>0.9,
    }
    
    puts hash.find_all{|a| a[0][0] == 'my' }.max[1]
    
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