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Home/ Questions/Q 385935
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T15:31:41+00:00 2026-05-12T15:31:41+00:00

barValues is an array I’m passing to a function. Within the function I have

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barValues is an array I’m passing to a function. Within the function I have this:

alert(barValues);

var sortedBarValues = barValues;
sortedBarValues.sort(function(a,b){return b - a});

alert(barValues);

I’m trying to end up with two arrays. barValues being the original array and sortedBarValues being a copy of that array, now sorted.

However, via the two alerts, I’m finding that barValues is ALSO being sorted. Why is that? What is the proper way to make a copy of an array so sort it separately from the original array?

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  1. Editorial Team
    Editorial Team
    2026-05-12T15:31:41+00:00Added an answer on May 12, 2026 at 3:31 pm

    With the statement var sortedBarValues = barValues;, you are not making a copy of the array. You are only making a reference. Both names refer to the same array.

    You can copy it with var sortedBarValues = barValues.slice();. The slice method is meant for slicing arrays, but if you don’t pass any parameters to it, it will make a copy.

    Keep in mind that using the slice method won’t work properly on multi-dimensional arrays. Copying multi-dimensional arrays is somewhat tricky, but jQuery’s extend function can do it for you.

    You can see information on how to copy an array in this post.

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