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Editorial Team
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Asked: 2026-05-13T05:29:38+00:00

Based on ideas presented in link I implemented several different sleep methods. One of

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Based on ideas presented in link I implemented several different “sleep methods”. One of this methods was the “binary sleep”, which looks like this:

while (System.currentTimeMillis() < nextTimeStamp)
{
sleepTime -= (sleepTime / 2);
sleep(sleepTime);
}

Because the check if the next time step is already reached takes place at the beginning I, would expect that the method is running too long. But the cummulative distribution of the simulation error (expected time – real time) looks like this: alt text http://img267.imageshack.us/img267/4224/errorvscummulativearran.jpg

Does somebody has an idea why I’m getting this results? Maybe the method System.currentTimeMillis() does not really return the current time?

BR,

Markus

@irreputable

When I made the evaluation I also created a bell curve by using a german statistic program. Because it was not possible to change caption, here is the english translation of all relevant items:

Häufigkeit = frequency

Fehler = error

Mittelwert = average

Std-Abw = standard deviation

alt text http://img694.imageshack.us/img694/2254/bellcurve.jpg

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1 Answer

  1. Editorial Team

    No it does not. Its young brother System#nanoTime() has a much better precision than System#currentTimeMillis().

    Apart from the answers in their Javadocs (click at the links here above), this subject was discussed several times here as well. Do a search on “currenttimemillis vs nanotime” and you’ll get under each this topic: System.currentTimeMillis vs System.nanoTime.

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