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Home/ Questions/Q 505513
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:36:23+00:00 2026-05-13T06:36:23+00:00

based on the answer to my previous question by BlausC i am now able

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based on the answer to my previous question by BlausC i am now able to use jquery to a certain extent. but now i need to add a checkbox control to the table created by jquery based on a postback from servlet. the code i am using is

 $("#linkInstr").click(function(){
   var arr=new Array();
   var cdid=$("#cboinstr option:selected");
    var code=$("#cbovendcode option:selected");
   $.get("trnDC?caseNo=21&insid="+cdid.text(),function(data){

      arr=data.split(",");
      var tbl= $("#tblDetails");
      $('<tr>').appendTo(tbl).append($('<td>'))
      .append($('<td>').text(code.val()))
      .append($('<td>').text(cdid.text()))
      .append($('<td>').text(arr[0]))
      .append($('<td>').text(arr[1]))
      .append($('<td>').text(arr[2]))
      ;

   })

})

any help will be greatly appreciated

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:36:24+00:00Added an answer on May 13, 2026 at 6:36 am

    Here’s a better way that includes the checkbox and is much more efficient.

     $("#linkInstr").click(function(){
    
       var arr=new Array();
       var contents;
    
       var cdid=$("#cboinstr option:selected");
       var code=$("#cbovendcode option:selected");
    
       $.get("trnDC?caseNo=21&insid="+cdid.text(),function(data){
          arr=data.split(",");
          contents = '<tr><td><input type="checkbox" /></td><td>' + cdid.text() + '</td><td>' + arr[0] + '</td><td>' + arr[1] + '</td><td>' + arr[2] + '</td></tr>';
    
          $("#tblDetails").append(content);
       });
    });
    
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