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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T09:34:57+00:00 2026-05-31T09:34:57+00:00

Based on this Stroustrup suggests that A pointer in a function should not represent

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Based on this

Stroustrup suggests that “A pointer in a function should not represent ownership”

Question> Can someone give me a little detail explanation? Best if an example is illustrated.

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  1. Editorial Team
    Editorial Team
    2026-05-31T09:34:58+00:00Added an answer on May 31, 2026 at 9:34 am

    A pointer is “owned” by some code if that code is responsible for deleting it, or for transferring ownership to someone else. Various smart pointers implement explicit ownership models. shared_ptr represents multiple pieces of code owning a pointer. unique_ptr represents only one piece of code that owns the pointer.

    What he’s saying is that if a function has a naked pointer (a pointer not in a smart pointer), it should not be considered to own it. If it is to claim some ownership of this pointer, it should either have been given a smart pointer as a parameter, or it should have stored the pointer it created with new in a smart pointer.

    He’s saying that only smart pointers own pointers. If a function takes a naked pointer as a parameter, it does not claim ownership of that pointer. If a function returns a naked pointer, you cannot claim ownership of that pointer.

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