Question

Based on this zlib-install-on-python, I need to run the following command

./configure –with-zlib=/usr/include

Question: Where can I find the configure in python 3.2?

user@ubuntu:~$ ls /usr/include/z* /usr/include/zconf.h
/usr/include/zlibdefs.h /usr/include/zlib.h

user@ubuntu:~/Downloads/Python-3.2$ ./configure –with-zlib=/usr/include
configure: error: invalid variable name: `–with-zlib'

Answer 1

You’ll need to run ./configure in your python install directory. This is wherever you unpacked the source tarball.

cd /path/to/python3.2
./configure --with-zlib=/usr/include

Notice that the --with-zlib argument is prefixed with two dashes, not one.

EDIT:
From ./configure -h,

–with-PACKAGE[=ARG] use PACKAGE [ARG=yes]

After trying ./configure --with-zlib=yes, which also produces the error, I think PACKAGE might be a non-standard package. However, to solve your problem (making sure python has zlib), you should just be able to do ./configure; make; sudo make install. You show that you have zlib.h, so this should reinstall python with support for zlib. I’ll see if I can find anymore info on the --with-PACKAGE option, but this should solve the root issue.