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Home/ Questions/Q 8768459
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T17:04:07+00:00 2026-06-13T17:04:07+00:00

Basic program to create a random number over 10000 and then print out the

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Basic program to create a random number over 10000 and then print out the number in a word format.

The problem is that for the eNum=atoi(Result[i]); line I get a compiler error saying about the variable std::string

Error:argument of type "char" is incompatible with parameter of type "const char*" 

What does that mean? I thought I was taking a single char and converting it into an int.

#include <iostream>
#include <stdlib.h>
#include <sstream>
#include <string>
using namespace std;


enum Numbers {Zero, One, Two, Three, Four, Five, Six, Seven, Eight, Nine, Point } eNum;

void main(void)
{
  int iRnd, iTemp;
  string Result;
  iRnd = rand() %  (sizeof(int)-10000) + 10000;
  ostringstream convert;
  convert << iRnd;
  Result = convert.str();

  cout << "\nRandmon number is: " << iRnd << endl << "Converted Number is : " << Result << endl;

  for (int i=0;i<Result.length();i++)
  {
    eNum = atoi(Result[i]);
    cout << eNum; 
    system("pause");
  }
}
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  1. Editorial Team
    Editorial Team
    2026-06-13T17:04:09+00:00Added an answer on June 13, 2026 at 5:04 pm

    The atoi() function expects a C string. Either get rid of your entire code and use

    int num = atoi(someString.c_str());
    

    for conversion, or in your code, change

    eNum = atoi(result[i]);
    

    to

    eNum = result[i] - '0';
    
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