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Home/ Questions/Q 405171
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:22:33+00:00 2026-05-12T17:22:33+00:00

Basically I am hacking a foxycart setup I run and I need to basically

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Basically I am hacking a foxycart setup I run and I need to basically hide a certain shipping option should a few things on the page exist…

1) that $value != United States (this is pulled dynamically from a text input but for purposes of showing you I’ve made it a static variable here
2) the number ‘.fc_cart_item’ occurs is only once
3) the text in ‘.fc_cart_item_quantity’ is only 1
and
4) the text in #fc_cart_table contains either Xyz or Zyx

Here is my statement that kinda works…

 var value = 'Australia';

if(    
    (    $value != 'United States'    &&    $('.fc_cart_item').size() < 2    &&    $('.fc_cart_item_quantity').text() < 2    )    &&    
    (    $('#fc_cart_table:contains(\'Zyx\')')    ||    $('#fc_cart_table:contains(\'Xyz\')')    )    
)

    {

       // do stuff

     }

Now this was working (whatever I put in // do stuff would occur) as I expect it when I had Xyz or Zyx in the cart… but then it was still doing stuff even when it was something other than Xyz or Zyx.

I’m coming from a PHP background so I don’t know if I’m doing my if statement correctly here.

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:22:33+00:00Added an answer on May 12, 2026 at 5:22 pm

    The if statement in your example will always return true because of the fact that the :contains selector does not return a boolean value that can be used safely for an if statement. Try this instead:

    value = "Australia";
    
    if( ( value != "United States" &&  $(".fc_cart_item").size() < 2 &&
       $(".fc_cart_item_quantity").text() < 2   ) &&
       ( $("#fc_cart_table").is(":contains('Zyx')") ||
       $("#fc_cart_table").is(":contains('Xyz')")    ) 
    {
    
       // do stuff
    }
    

    BTW, your can tell that you’re from a PHP background with your $value syntax… 🙂

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