Question

Basically I am working a site store and having problems with it. Nothing online seems to have what I need to figure out. I am having the first if else statement working fine and the second not working properly. Here is the coding tell me what is wrong or what I can do different.

<?php
$adsql = mysql_query("SELECT * FROM store_items WHERE userid='$id2'");
while($adrow = mysql_fetch_array($adsql)){
    $type = $adrow['type'];(this is int)
                               $item = $adrow['id'];
    if ($type == 1) {
        $item1 = "<center>You have bought this already</center>";
    } else {
        $item1 = This is where item1 is bought

            }
    if ($type == 2) {
        $item2 = "<center>You have bought this already</center>";
    } else {
        $item2 = This is where item2 is bought
            </table>
            ";
              }
      }
    ?>

Its retrieving the last number not all the numbers which in return only showing 1 of if else statements instead of both. Any idea what is wrong be a appreciated.

Answer 1

The lines:

$item1 = This is where item1 is bought

and

$item2 = This is where item2 is bought

Should be:

$item1 = "This is where item1 is bought";

and

$item2 = "This is where item2 is bought";

Without the quotes, the statements are syntactically incorrect.