Question

Basically I have a block of html that I want to echo to the page and the html has the $ sign in it and the php thinks it is a variable so $1 is treated as the variable not the value and is not displayed.

There is the standard answers here but none are working: PHP: How to get $ to print using echo

My next idea is to split the string at the $ and echo each part out.

Here is the code I have tried echo and print.

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;
    //$s = str_replace('$', '@', $s);
    $s = str_replace('$', '\$', $s);
    //echo  "$s" . "<br>";
    print $s;
}

All help appreciated.

OK I solved by using the character code value for $

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;       
    $s = str_replace('$', '$', $s);
    echo  $s . "<br>";
}

I figured I should just post it anyway.

Thanks,

Mat

Answer 1

You’re doing it in the wrong place. Variable interpolating is done when double quoted string literal (which in your case is stored within $rowmk->longdescription is daclared. Once it’s done, you can’t really do anything to get your $s back.

Solution, do proper escaping, when you declare the string.