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Asked: 2026-05-25T22:27:33+00:00

Basically I have the following query: SELECT DISTINCT users.ID, users.name FROM users INNER JOIN

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Basically I have the following query:

SELECT DISTINCT users.ID, users.name
FROM users 
INNER JOIN usersSkills ON users.ID = usersSkills.userID 
INNER JOIN usersLanguages ON users.ID = usersLanguages.userID 
WHERE activated = "1" 
AND type = "GRADUATE" 
AND usersSkills.skillID IN(2, 21)
AND usersLanguages.languageID IN(2, 22)

I need to match the skillID and languageID to each parameter passed in the IN() function at the moment on each of those it will serve up a result if either parameter is found.

So essentially i want to only see results if the skill ID of 2 AND 21 are found on the skills table and the same idea for the languages…

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1 Answer

  1. Editorial Team

    Use a GROUP BY (this will also eliminate the need for SELECT DISTINCT) to get an aggregate count and a HAVING clause to make sure the count of distinct elements returned matches the number of elements you’re searching for.

    SELECT users.ID, users.name
FROM users 
INNER JOIN usersSkills ON users.ID = usersSkills.userID 
INNER JOIN usersLanguages ON users.ID = usersLanguages.userID 
WHERE activated = "1" 
AND type = "GRADUATE" 
AND usersSkills.skillID IN(2, 21)
AND usersLanguages.languageID IN(2, 22)
GROUP BY users.ID, users.name
HAVING COUNT(DISTINCT usersSkills.skillID) = 2
   AND COUNT(DISTINCT usersLanguages.languageID) = 2
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