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Home/ Questions/Q 7586109
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:20:38+00:00 2026-05-30T19:20:38+00:00

Basically I need to create a string with $_GET[‘param’] , something like: $myString =

  • 0

Basically I need to create a string with $_GET['param'], something like:

$myString = $_GET['param'] . 'abc';

When $_GET['param'] isn’t isset i am perfectly fine with $myString being just ='abc'

  • So I can do something like this:

    $myString = @$_GET['param'] . 'abc';
    
  • Or use the standard way with isset:

    if (!isset($_GET['param']))
       $_GET['param'] = '';
    
    $myString = $_GET['param'] . 'abc';
    

In this case using the @ suppresser is considering such a bad pratice?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:20:40+00:00Added an answer on May 30, 2026 at 7:20 pm

    The most elegant thing IMHO would be to wrap that in a nice getter function, something like:

    function _getParam($param, $default = '') {
        if (!isset($_GET[$param]))
           return $default;
        return $_GET[$param];
    
    }
    
    
    $myString = _getParam('param').'abc';
    

    yes123 note:
    As dvir said having a getter function for input variables in your framework can be handy. But this _getParam suffers of this problem:

    Let’s see we make a typo in our code, we want to access $_GET['param'] and istead of it we type:

    _getParam('parm')
    

    Our code will work without generting any problems and we will have hard time finding the error.

    So I thought we could modify the function presented to something like:

    function _get() {
      $key = func_get_arg(0);
    
      if (func_num_args()==2) {
        if (!isset($_GET[$key]))
          return func_get_arg(1);  
      }
    
      return $_GET[$key];
    }
    

    This ensures that when we typo it with _get('parm') we will get a notice throwed normally. But when we use it with 2 param we get out default value:

    _get('param','myDefaultValue');
    
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