Question

Basically I need to find all the ids with more than 1 name

so the output should be

 (2,a)(2,b)(4,a)(4,b)(4,c) 

id name

1 a

2 a

2 b

3 c

3 c

4 a

4 b

4 c

I got a query working

select * from (select distinct * from test) t group by t.id having count(*) > 1

But I think there might be a simpler solution, so yeah, is there a simply solution, if yes, what is it? Thank in advance.

Answer 1

Select
  Id,
  Name
FROM test 
Group By Id, Name
Having Count(Distinct(Name)) > 1